Simple Wiring Diagram is making my head hurt
Posted: Tue Apr 08, 2008 3:02 pm
I was staring at this last night while working from home late into the evening and I don't get it:
http://www.fender.com/support/diagrams/ ... 02APg2.pdf
Now Why the FUCK is the tone it's most trebly when the tone pot is on full (i.e. the Resistance between the wiper and the cap is 1meg)?
This is the circuit that is being made:
The volume is simple, when set to full (1 meg) you have full output as the signal takes the least resistance path straight to the wiper, which is basically connected to the 'top' lug. Resistance between middle and right lug is 1meg, that's why you don't get much treble loss and maximum outupt.
but that low pass filter really confuses me on the right, I always would do them as signal into a resistor and cap in series to ground, with the output tapped of the mid point, and work out the break freq by 1/(2x pi x RC) and in that case you'd set R to 0 for the maximum treble.
However this isn;t that type of low pass at all, and in fact when R is at it's max like the volume yuo have the most treble. Is tihs as simple as that meaning that it means the signal has to travel through 1 meg to be filtered to ground by the capacitor and therefore full R = least treble loss? Is it this simple or am I missing something complicated? When R is 0 you have a Resistor and a Cap in Parallel with the signal to ground - that's not exactly a classic filter.
I'm a dunce.
http://www.fender.com/support/diagrams/ ... 02APg2.pdf
Now Why the FUCK is the tone it's most trebly when the tone pot is on full (i.e. the Resistance between the wiper and the cap is 1meg)?
This is the circuit that is being made:
The volume is simple, when set to full (1 meg) you have full output as the signal takes the least resistance path straight to the wiper, which is basically connected to the 'top' lug. Resistance between middle and right lug is 1meg, that's why you don't get much treble loss and maximum outupt.
but that low pass filter really confuses me on the right, I always would do them as signal into a resistor and cap in series to ground, with the output tapped of the mid point, and work out the break freq by 1/(2x pi x RC) and in that case you'd set R to 0 for the maximum treble.
However this isn;t that type of low pass at all, and in fact when R is at it's max like the volume yuo have the most treble. Is tihs as simple as that meaning that it means the signal has to travel through 1 meg to be filtered to ground by the capacitor and therefore full R = least treble loss? Is it this simple or am I missing something complicated? When R is 0 you have a Resistor and a Cap in Parallel with the signal to ground - that's not exactly a classic filter.
I'm a dunce.